SOLUTION: please help me solve this: {{{ 3rt( 27x^9y^4z^7) }}} i am not sure if i entered this is correctly but i hope that i did. It is the cube root of 27x^9y^4z^7

SOLUTION: please help me solve this: {{{ 3rt( 27x^9y^4z^7) }}} i am not sure if i entered this is correctly but i hope that i did. It is the cube root of 27x^9y^4z^7

Algebra.Com

Question 66938: please help me solve this:

i am not sure if i entered this is correctly but i hope that i did. It is the cube root of 27x^9y^4z^7
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
The cube root can be expressed as

Now simply multiply each exponent by 1/3 and take the cube root of 27

So 27 to the one-third power (the cube root of 27) is 3

Multiply the exponents

Simplify. There's the simplified expression.
Or it could look like this

Either way they are both equal.
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