Question 66729: What would the answer be for 12+2(k+3)=3k-6?
Could you please show the work so i can understand it. Found 2 solutions by stanbon, Edwin McCravy:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 12+2(k+3)=3k-6
Use the distributive property to get:
12+2k+6 = 3k-6
Combine like terms on the left side to get:
2x+18=3k-6
Add 6 to both sides to get:
2x+24=3x
Subtract 2x from both sides to get:
x=24
Cheers,
Stan H.
What would the answer be for
12 + 2(k + 3) = 3k - 6
First get rid of the parentheses on the left by
multiplying the +2 times both terms inside it,
the k and the +3, giving +2k + 6
12 + 2k + 6 = 3k - 6
Add the 12 and the +6, getting 18
18 + 2k = 3k - 6
Get rid of the 18 on the left by adding -18 to both
sides:
18 + 2k = 3k - 6
-18 -18
------------------
2k = 3k - 24
Get rid of the 3k on the right by adding -3k to both
sides:
2k = 3k - 24
-3k -3k
-------------
-k = -24
Now write -k as -1k
-1k = -24
Now we get rid of the -1 coefficient of k, we divide
both sides by -1:
-1k -24
————— = —-———
-1 -1
The -1's cancel on the left, leaving only k.
-24 divided by -1 on the right gives +24 on the
right and we are left with:
k = 24
The solution is 24.
Edwin
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