SOLUTION: 7a-4b-[5a-3{b-2(a-b)}]

Question 662730: 7a-4b-[5a-3{b-2(a-b)}]
Answer by ladyluck4772(11) (Show Source): You can put this solution on YOUR website!
If you have trouble following the steps I show, I have given a detailed explaination following these steps.

7a-4b-[5a-3{b-2(a-b)}]
7a-4b-[5a-3{b-2a+2b}
7a-4b-[5a-3{3b-2a}
7a-4b-[5a-9b+6a]
7a-4b-[11a-9b]
7a-4b-1[11a-9b]
7a-4b-11a+9b

-4a+5b (your final answer)

Remember your order of operations first. What part of the problem do you work first? Whatever is inside the parentheses {}, which in this case is:

{b-2(a-b)}

However, there are () inside of {}. In this case you would multiply the 2 by (a-b) first.

{b-2a+2b} Plug this in the original equation where {b-2(a-b)} was. This leaves you with the rest of the problem to solve.

7a-4b-[5a-3{b-2a+2b] Now solve what is inside the brackets [].

7a-4b-[5a-3b+6a-6b]

Combine like terms inside the [] leaving:

7a-4b-[11a-9b]

Now drop the brackets and combine like terms. Be sure to distribute the negative sign (-) after the 4b before dropping the brackets.

7a-4b-[11a-9b]
7a-4b-11a+9b
-4a+5b (answer)

Please ask if have any questions. :)

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