SOLUTION: 5/x-2-5/x^2-4=1/x+2

Question 65502: 5/x-2-5/x^2-4=1/x+2
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
5/x-2-5/x^2-4=1/x+2
5/x-1/x-5/x^2=2+2+4
4/x-5/x^2=8 find a common denominator for the /x &/x^2 terms (x^2) & add
(4x-5)/x^2=8 now cross multiply
8x^2=4x-5
8x^2-4x+5=0
using the quadratic equation we solve for x thus
x=(-b+-sqrt[b^2-4ac])/2a
x=(4+-sqrt[-4^2-4*8*5])/2*8
x=(4+-sqrt[16-160])/16
x=(4+-sqrt-144])/16
x=(4+-12i)/16
x=4/16+12i/16
x=.25+.75i solution
x=(4-12i)/16
x=4/16-12i/16
x=.25-.75i solution
####################################################
MERRY CHRISTMAS

RELATED QUESTIONS
{{{5/(x-2)-5/(x^2-4)=1/(x+2)}}} (answered by funmath)

X^2/4-X/1=5/4 (answered by sdmmadam@yahoo.com)

4/x+1=2/5 (answered by jim_thompson5910)

5/4 x=... (answered by tommyt3rd)

(x+2)(x+1)-2(x+5) (answered by JBarnum)

5(x-4)=2(x+1)-7 (answered by bacos)

{{{5^(x+2)}}}={{{4^(1-x)}}} (answered by Edwin McCravy)