SOLUTION: 1/4x+1/3y=11
1/3x+1/4y=10;
Algebra.Com
Question 644353: 1/4x+1/3y=11
1/3x+1/4y=10;
Found 2 solutions by kekegeter , Alan3354:
Answer by kekegeter (97) (Show Source): You can put this solution on YOUR website!
1. 1/3x + 1/4y =10;
x/3 + 1/2^2y =10
x/3 + y/2^2 =10
4x+3y/3*2 =10
4x = -3y + 120
x = 3(-y+40)/4
2. 1/4x + 1/3y =11
1/2^2x + y/3 =11
x/2^2 + y/3 =11
3x+ 4y/2^2*3 =11
3x - 4y + 132
x = 4(-y+33)/3
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
1/4x+1/3y=11
1/3x+1/4y=10
===============
x/4 + y/3 = 11
x/3 + y/4 = 10
------------
Multiply by 12 to eliminate fractions
3x + 4y = 132
4x + 3y = 120
-------------
9x + 12y = 396
16x+ 12y = 480
--------------- Subtract
-7x = - 84
x = 12
------
y = 16
====================
The other tutor treated it as 2 problems. You didn't say it was a system, or what you wanted to do.
RELATED QUESTIONS
4x-3y=11; 3x+7y=-1 (answered by Fombitz)
1/2x - 1/3y - 1/2z = 1/10
1/3x - 1/4y + 1/3z = 1/8
1/4x - 1/5y + 1/4z =... (answered by Fombitz)
1/2x - 1/3y - 1/2z = 1/10
1/3x - 1/4y + 1/3z = 1/ 8
1/4x - 1/5y + 1/4z =... (answered by Fombitz)
4x - 1 = x + 11
4x - x = 11 - 1
3x =... (answered by sudhanshu_kmr)
1. 4x+3y=1, x=1-y
2. 2x-y=6, -x+y=-1
3. 6x-y=3, 4x-2y=-2
4. 2x+3y=7, x=1-4y
5.... (answered by AnlytcPhil)
2x+3y=1... (answered by checkley71)
Solve using Cramer's Rule:
3x + 5y = 1
4x - 3y =... (answered by robertb)
Help!
1.{{{y=-x+5}}}
{{{x-4y=10}}}
2.{{{x-y=2}}}... (answered by Alan3354)
3x-3y-1=3x-5y... (answered by Alan3354,josgarithmetic)