Suppose that A, B, and C are positive constants and that x + y = C. Show that the minimum value of Ax² + By² occurs when x = and y =
We know that if A > 0, the minimum value of y = Ax² + Bx + C
occurs when x =
To avoid conflict of letters we re-write that as
We know that if P > 0, the minimum value of y = Px² + Qx + R
occurs when x =
Since x + y = C, y = C - x, so
Minimum value of Ax² + By² =
Minimum value of Ax² + B(C - x)² =
Minimum value of Ax² + B(C - x)(C - x) =
Minimum value of Ax² + B(C² - 2Cx + x²) =
Minimum value of Ax² + BC² - 2BCx + Bx² =
Minimum value of Ax² + Bx² - 2BCx + BC² =
Minimum value of (A + B)x² - 2BCx + BC²
And by the rule above:
We know that if P > 0, the minimum value of y = Px² + Qx + R
occurs when x =
Let P = (A + B), Q = -2BC, and R = BC²
Minimum value of (A + B)x² - 2BCx + BC²
occurs when x = = =
and since y = C - x, the value of y when x = is
y = C - = - =
· - = - =
- = = .
Edwin