SOLUTION: [(1/a)-(1/b)] / [(1/a^2)-(1/b^2)]= a) (a-b)/ab b) (a+b)/ab c) ab/(a-b) d) ab/(a+b) e) (1/a)-(1/b)

Question 625845: [(1/a)-(1/b)] / [(1/a^2)-(1/b^2)]=
a) (a-b)/ab
b) (a+b)/ab
c) ab/(a-b)
d) ab/(a+b)
e) (1/a)-(1/b)

Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
[(1/a)-(1/b)] / [(1/a^2)-(1/b^2)]=
= [(b-a)/ab]/[(b^2-a^2)/a^2b^2]
= [(b-a)/ab]a^2b^2/(b-a)(b+a)
= ab/a+b

Answer: d) ab/(a+b)
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