SOLUTION: Simplify the following product of complex numbers.
(-3 + 2i) . (-4 - 8i)
Thank you...For any help please so how you did it
so I can learn.. OKay?
Algebra.Com
Question 625331: Simplify the following product of complex numbers.
(-3 + 2i) . (-4 - 8i)
Thank you...For any help please so how you did it
so I can learn.. OKay?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Simplify the following product of complex numbers.
(-3 + 2i)*(-4 - 8i)
Use the * for multiply
(-3 + 2i)*(-4 - 8i) = -3*(-4 - 8i) + 2i*(-4 - 8i) same as any 2 binomials
= 12 + 24i - 8i - 16i^2
= 12 + 16i - 16i^2
i^2 = -1
--> 12 + 16i + 16
= 28 + 16i
RELATED QUESTIONS
Simplify the following product of complex numbers.
(-3 + 2i) • (-4 – 8i)
(answered by Tatiana_Stebko)
7. Simplify the following product of complex numbers.
(-3 + 2i) · (-4 – 8i)
(answered by MathLover1)
Simplify the following product of complex numbers.
(4 – 8i) • (-5 + 2i)
(answered by stanbon)
Please help with this. How do I add complex numbers?
1. (3+2i)+(4-4i)
2. (1+4i)+... (answered by solver91311)
Subtract the complex numbers and simplify: 3+2i/1+2i-1/1/2i= Help! Thank... (answered by sarah_adam)
Use a graph to demonstrate the operation of these complex numbers:
1) (7-6i)+(-5-2i)
(answered by stanbon)
Simplify the following product of complex numbers.
(5 + 3i) · (6 – 2i)
Any help... (answered by jessica43)
help please. find the product of these complex numbers. if possible show the steps. thank (answered by Alan3354)
Hey so i'm working on complex numbers in my algebra 2 class and I have not done my... (answered by jim_thompson5910)