SOLUTION: I have two algebra I word problems i need help setting up. I would like if you can explain the steps of setting up. Here it is: Problem #1 The length of a rectangle is 2 1/2 tim

Question 612274: I have two algebra I word problems i need help setting up. I would like if you can explain the steps of setting up.
Here it is:
Problem #1
The length of a rectangle is 2 1/2 times its width. Its area is 90 square units. What are its dimensions? (Hint: length times width = area)
Let w= width in units.
L=(2 1/2)w= 5w/2 = length in units

Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
now multiply length by width
(5w/2)*w=90
5w^2=45
w^2=9
w=3
5w/2=15/2=L
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