SOLUTION: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
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Question 59719This question is from textbook
: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
This question is from textbook
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
L=2W+2
2L+2W=52
2(2W+2)+2W=52
4W+4+2W=52
6W=52-4
6W=48
W=48/6
W=8 THE WIDTH IS 8 CM. THEN
L=2*8+2
L=16+2
L=18 THE LENGTH IS 18 CM.
PROOF
2*18+2*8=52
36+16=52
52=52
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