# SOLUTION: a jar containing only nickels and dimes contains a total of 50 coins. the value of all the coins in the jar is \$4.10. find the amount of nickels and dimes that are in the jar?

Algebra ->  Algebra  -> Expressions-with-variables -> SOLUTION: a jar containing only nickels and dimes contains a total of 50 coins. the value of all the coins in the jar is \$4.10. find the amount of nickels and dimes that are in the jar?      Log On

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 Click here to see ALL problems on Expressions-with-variables Question 592268: a jar containing only nickels and dimes contains a total of 50 coins. the value of all the coins in the jar is \$4.10. find the amount of nickels and dimes that are in the jar?Answer by jim_thompson5910(28595)   (Show Source): You can put this solution on YOUR website!Let d = number of dimes and q = number of quarters Since "a jar containing only nickels and dimes contains a total of 50 coins", we know that d+q = 50 Basically take the individual totals of each and add them up to get 50 coins total. This is equation 1. -------------------------------------------------------------------------- If you have d dimes, then the total value of them is 0.1d dollars. If you have q quarters, then the total value is 0.25q dollars These two add to: 0.1d + 0.25q and this expression is equal to \$4.10, so... 0.1d + 0.25q = 4.10 Now multiply everything by 100 to get 10d + 25q = 410 This is equation 2. ------------------------------------------------------------------------ So we have two equations d+q = 50 10d + 25q = 410 with 2 unknowns. So you can either use substitution or elimination to solve. I recommend substitution. Solve for d to get d = 50 - q, then substitute this into 10d+25q = 410 to get 10(50-q) + 25q = 410 From here, you can solve for q, which I'll let you do. Once you have the value of 'q', use it to find the value of 'd'.