SOLUTION: find the point of intersection for the lines below using the elimination 3x+2y=16 2x-3y=-11

Question 55290: find the point of intersection for the lines below using the elimination
3x+2y=16
2x-3y=-11
Answer by tutorcecilia(2152) (Show Source): You can put this solution on YOUR website!
-2(3x+2y=16)
+3(2x-3y=-11)
____________
.
.
-6x-4y=-32
+6x-9y=-33
____________
.
.
-6x-4y=-32
+6x-9y=-33
____________
0x-13y=-65
.
.
-13y=-65
y=-65/-13
y=65/13
y=5
.
Plug (y=5) back into either original equation and solve for x:
3x+2y=16
3x+2(5)=16
3x+10=16 [Solve for x]
3x=6
x=6/3
x=2
.
Plug-in the value of x and y back into the original equations.
2x-3y=-11
2(2)-3(5)=-11
4-15=-11
-11=-11

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