SOLUTION: pg. 129 problem 13 How do you solve this prblem? Warren has 40 coins (all nickels, dimes, and quarters)worth $4.05. He has 7 more nickels than dimes. How many quarters does Warre

Question 55271This question is from textbook Algebra Structure and Method Book 1
: pg. 129 problem 13
How do you solve this prblem?
Warren has 40 coins (all nickels, dimes, and quarters)worth $4.05. He has 7 more nickels than dimes. How many quarters does Warren have? This question is from textbook Algebra Structure and Method Book 1

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Warren has 40 coins (all nickels, dimes, and quarters)worth $4.05. He has 7 more nickels than dimes. How many quarters does Warren have?
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Let number of dimes be "x" ; Value of those dimes is 10x cents.
Number of nickels is "x+7" ; Value of those nickels is 5(x+7)=5x+35 cents
Number of quarters is "40-2x-7"="33-2x";Value of those is 25(33-2x)=825-50x
EQUATION:
value + value + value = 405 cents
10x+5x+35+825-50x=405
-35x=-420
x=12 (#of dimes)
33-2x=33-24=9 (# of quarters).
Cheers,
Stan H.
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