SOLUTION: To be honest I am not sure what category it is. Can you please help me, I only know the first steps? Please read everything that I worte. It's only one problem, I just have a few q
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Question 54685This question is from textbook
: To be honest I am not sure what category it is. Can you please help me, I only know the first steps? Please read everything that I worte. It's only one problem, I just have a few quetions and I hope you can explain it clearly enought to me. Thank You for the help!The section of my book says "Solving Equations with variables on Both Sides" The problem is....
9(b-4)-7b=5(3b-2)
9b-36-7b=15b-2
this is where I kinda get confused, do you minus 9b from 9b then minus 9b from 7b or do you add 7b to 7b then add 7b to 9b. Can you do -36-2? Can you tell me what some of these steps are and why it is what it is please? For this problem I only know how to combine like terms and do the little division thing at the end. I can do easier problems like 12y+21=9y , 12y-12y+21=9y-12y, 21=-3y. -3y divided by -3 cancels out then you do it to the other side 21 divided by -3 = -7 so y=-7
This question is from textbook
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
9(B-4)-7B=5(3B-2)
9B-36-7B=15B-10
9B-7B-15B=36-10
-13B=26
B=26/-13
B=-2
PROOF
9(-2-4)-7(-2)=5(3[-2]-2)
9(-6)+14=5(-6-2)
-54+14=5(-8)
-40=-40
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