SOLUTION: A passenger train leaves traveling 60 mph. A freight train leaves at the same time traveling 40 mph and travels the same distance. The passenger train arrives at its destination

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Question 54382: A passenger train leaves traveling 60 mph. A freight train leaves at the same time traveling 40 mph and travels the same distance. The passenger train arrives at its destination 1.5 hours earlier than the freight train. How long does each train take to make the trip?
Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website!
1st train's rate: 40
1st train's time: h
Distance = rate * time
Distance = 40h
2nd train's rate: 60
2nd train's time: h - 1.5
Distance = rate * time
Distance = 60h - 90
They both travel the same distance.
40h = 60h - 90
90 = 20h
4.5 = h
Freight Train's Time ~> 4.5 hours
Passenger Train's Time ~> 3 hours