SOLUTION: Akay How do I set this up when : p(x) = x^2 -x-5 and r(x) = 2x-1, evaluate (r o p)(6) The o in the (rop) is a small funny oval shape symbol that I don't understand what it me

Algebra ->  Expressions-with-variables -> SOLUTION: Akay How do I set this up when : p(x) = x^2 -x-5 and r(x) = 2x-1, evaluate (r o p)(6) The o in the (rop) is a small funny oval shape symbol that I don't understand what it me      Log On


   

Question 54175: Akay How do I set this up when :
p(x) = x^2 -x-5 and r(x) = 2x-1, evaluate (r o p)(6)
The o in the (rop) is a small funny oval shape symbol that I don't understand what it means? Thanks for any help.
Found 2 solutions by stanbon, funmath:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
p(x) = x^2 -x-5 and r(x) = 2x-1, evaluate (r o p)(6)
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The funny thing means you should form the composite function
of r in p(6)
To do this you 1st find P(6)=6^2-6-5=25
Then you evaluate r at 25: r(25)=2(25)-1=49
So (r o p)6 = r[p(6)]=r[25]=49
Cheers,
Stan H.

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
rop(x) means r composite p of x. It means that you put the p function everywhere there's an x in the r function.
p%28x%29=x%5E2-x-5
r%28x%29=2x-1
rop%28x%29=r%28x%5E2-x-5%29
r%28x%5E2-x-5%29=2%28x%5E2-x-5%29-1
r%28x%5E2-x-5%29=2x%5E2-2x-10-1
r%28x%5E2-x-5%29=2x%5E2-2x-11
rop%28x%29=2x%5E2-2x-11
Because you need to find rop(6) substitute 6 in for the x in the composite function.
rop%286%29=2%286%29%5E2-2%286%29-11
rop%286%29=2%2836%29-2%286%29-11
rop%286%29=72-12-11
highlight%28rop%286%29=49%29
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Another way to do it is to find p(6) and then substitute that answer into r(x).
p%286%29=%286%29%5E2-6-5
p%286%29=36-6-5
p%286%29=25
r%2825%29=2%2825%29-1
r%2825%29=50-1
r%2825%29=49
Therefore highlight%28rop%286%29=49%29
Happy Calculating!!!