SOLUTION: I am not sure how to simplify this problem: {{{ (3^(n+2)-3^n)/(3^(n-1)+3^n) }}} I know that if there was one monomial in the denominator than i would divide each monomial in the n

Algebra ->  Expressions-with-variables -> SOLUTION: I am not sure how to simplify this problem: {{{ (3^(n+2)-3^n)/(3^(n-1)+3^n) }}} I know that if there was one monomial in the denominator than i would divide each monomial in the n      Log On


   

Question 537872: I am not sure how to simplify this problem: +%283%5E%28n%2B2%29-3%5En%29%2F%283%5E%28n-1%29%2B3%5En%29+
I know that if there was one monomial in the denominator than i would divide each monomial in the numerator by the denominator but i am not sure what to do here.
Thank You
Found 2 solutions by Alan3354, solver91311:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
I am not sure how to simplify this problem: +%283%5E%28n%2B2%29-3%5En%29%2F%283%5E%28n-1%29%2B3%5En%29+
I know that if there was one monomial in the denominator than i would divide each monomial in the numerator by the denominator but i am not sure what to do here.
----------------------
+%283%5E%28n%2B2%29-3%5En%29%2F%283%5E%28n-1%29%2B3%5En%29+
Divide NUM and DEN by 3^n
= %283%5E2+-+1%29%2F%283%5E%28-1%29+%2B+1%29
= 8%2F%284%2F3%29
= 6

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Remember that



So



is just another way to say



Likewise



So let's do a little substituting:



Looking at the numerator, we have 9 of something minus 1 of the same thing. Looking at the denominator, we have 1/3 of something plus 1 of the same thing. Hence:



goes away and you are left with



John

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