SOLUTION: Mary and Lucy both leave from the same bus station. Mary drives 10mph slower than Lucy. In three hours, the are 260 miles apart. How do you set up an equation to solve? ~Confide

Algebra ->  Expressions-with-variables -> SOLUTION: Mary and Lucy both leave from the same bus station. Mary drives 10mph slower than Lucy. In three hours, the are 260 miles apart. How do you set up an equation to solve? ~Confide      Log On


   



Question 53211: Mary and Lucy both leave from the same bus station. Mary drives 10mph slower than Lucy. In three hours, the are 260 miles apart. How do you set up an equation to solve?
~Confidently Confused~

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Mary and Lucy both leave from the same bus station. Mary drives 10mph slower than Lucy. In three hours, the are 260 miles apart. How do you set up an equation to solve?
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I am assuming they are traveling in opposite directions, so the distances they travel will be added together to get 260 miles
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Let s = Lucy's speed; Then [s-10] = Mary's speed
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Write a distance equation, remember d = time * Speed
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Both girls are traveling for 3 hours
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Lucy's Dist + Mary's Dist = 260
3*s + 3[s-10] = 260
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Solving this equation will give you Lucy's speed (s).