What is solution to this system of equations? 2x + 4y = 2/3 3x - 5y = -10 Maybe we can make it into a system that you already know how to find the solution to. Clear the first one of its fraction by multiplying it thru by the LCD of 3. (3)·2x + (3)·4y = (3)·2/3 6x + 12y = (3)·2/36x + 12y = 2 Now you have this system with no fractions 6x + 12y = 2 3x - 5y = -10 Can you solve that system by elimination? If not post again and ask how to solve it. Its solution is this: (x,y) = (-5/3, 1) Edwin