SOLUTION: Solve in terms of X. The sum of three numbers is 75. The second number is 8 more than the first. I keep trying to set this up as follow: Let 1st number= X Let 2nd number= X

Algebra ->  Algebra  -> Expressions-with-variables -> SOLUTION: Solve in terms of X. The sum of three numbers is 75. The second number is 8 more than the first. I keep trying to set this up as follow: Let 1st number= X Let 2nd number= X       Log On

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Question 52246: Solve in terms of X. The sum of three numbers is 75. The second number is 8 more than the first.
I keep trying to set this up as follow:
Let 1st number= X
Let 2nd number= X + 8
Let 3rd number= 75-x-(x+8)
When I set it up as x+x+8+75-x-(x+8)=75 I am unable to come up with the value of X. Help please. Thanks

Answer by rchill(405) About Me  (Show Source):
You can put this solution on YOUR website!
We know nothing about the third number, so let's call it y. So, we have 75=x%2B%28x%2B8%29%2By which simplifies to 75=2x%2B8%2By. Further simplification results in 67=2x%2By. Continue solving for x and we get 67-y=2x and finally%2867-y%29%2F2=x.