SOLUTION: x^3=-3x^2+10x
So, I don't know if I'm doing this right...
-3x^2+10x-x^3=0
x(-x^2-3x+10)=0
x(-x-2)(-x-5)
-x-2=0 -x-5=0
The -x doesn't seem right...is it?
Algebra.Com
Question 517820: x^3=-3x^2+10x
So, I don't know if I'm doing this right...
-3x^2+10x-x^3=0
x(-x^2-3x+10)=0
x(-x-2)(-x-5)
-x-2=0 -x-5=0
The -x doesn't seem right...is it?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x^3=-3x^2+10x
---
x^3+3x^2-10x = 0
x[x^2+3x-10] = 0
Factor:
x(x-5)(x+2) = 0
-----------
x = 0 or x = 5 or x = -2
===============================
Cheers,
Stan H.
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