SOLUTION: x^3=-3x^2+10x So, I don't know if I'm doing this right... -3x^2+10x-x^3=0 x(-x^2-3x+10)=0 x(-x-2)(-x-5) -x-2=0 -x-5=0 The -x doesn't seem right...is it?

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Question 517820: x^3=-3x^2+10x
So, I don't know if I'm doing this right...
-3x^2+10x-x^3=0
x(-x^2-3x+10)=0
x(-x-2)(-x-5)
-x-2=0 -x-5=0
The -x doesn't seem right...is it?

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
x^3=-3x^2+10x
---
x^3+3x^2-10x = 0
x[x^2+3x-10] = 0
Factor:
x(x-5)(x+2) = 0
-----------
x = 0 or x = 5 or x = -2
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Cheers,
Stan H.
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