SOLUTION: Please help me with this one. I am in no way good at this but I am trying to keep from asking for help, thank! Solve each of the following systems by substitution.

Question 51339: Please help me with this one. I am in no way good at this but I am trying to keep from asking for help, thank!
Solve each of the following systems by substitution.
5x - 2y = -5
y - 5x = 3
Found 2 solutions by rapaljer, chuy605:
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
To do this by substitution, the first step is to solve for one of the variables in terms of the other. The easiest one to solve for is the y in the second equation. Do this by adding +5x to each side of the equation.
y = 5x + 3

Now, subsitute this into the first equation:
5x - 2y = -5
5x - 2(_____) = -5
5x - 2(5x+3) = -5

5x - 10x - 6 = -5
-5x - 6 = -5
-5x-6+6=-5+6
-5x=1

Substitute back into the equation in which you solved for y:
y=5x+3
y=5(-1/5)+3
y=-1+3= 2

The solution is (,2)
Also, see my website by clicking on my tutor name "rapaljer" anywhere in algebra.com, and look for "Math in Living Color," then Intermediate Algebra, and look for Section 5.02, Systems of Inequalities. There are LOTS of problems solved in Living Color!!

R^2 at SCC

Answer by chuy605(1) (Show Source): You can put this solution on YOUR website!
1st chose an easy equation like: Y-5x=3
and move the -5x to the right side so you get Y=5x+3
then you re-place Y with (5x+3) in the 2nd equation
and you get this 5x-2(5x+3)=-5
5x-10x-6=-5
-5x-6+6=-5+6
-5x=1
x=-1/5
just re-place the x to 5(-1/5)-2y=-5 to get Y
-1-2y=-5
-2y=-4
Y=2
check
5(-1/5)-2(2)=-5
-1-4=-5
-5=-5
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