SOLUTION: A jar contains 40 coins consisting of dimes and quarters and having a total value of $4.90. How many of each kind of coin are there?
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Question 50892This question is from textbook Algebra and Trigonometry Structure and Method.
: A jar contains 40 coins consisting of dimes and quarters and having a total value of $4.90. How many of each kind of coin are there?
This question is from textbook Algebra and Trigonometry Structure and Method.
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
Think of:
d = number of dimes
q = number of quarters
d + q = 40 which can be: d = 40 - q
plug:
0.1d + 0.25q = 4.90
0.1(40 - q) + 0.25q = 4.90
4 - 0.1q + 0.25q = 4.90
0.15q = 0.90
q = 6
plug: d = 40 - q = 40 - 6 = 34
34 dimes and 6 quarters
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