SOLUTION: I think I'm just confused by the terminology. Saxon asks to solve the following by "elimination" to solve equivalent fractions, but with only positive numbers on the variable side

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Question 50825This question is from textbook Saxon Algebra 1
: I think I'm just confused by the terminology. Saxon asks to solve the following by "elimination" to solve equivalent fractions, but with only positive numbers on the variable side, I can't get the problem to work out as in their examples - each of which has at least one negative number.
a. 4y + 3x = -7 and 3y + 2x = -6
They say to multiply each equation by one of the variable terms from the other...i.e. multiply first one by 2x and the other by 3x....doesn't work out. ?????? I end up with a plus 6x in both rather than a +6x and a -6x which would cancel out each other, leaving room to solve for y.
I'm missing something......:-(
Rebecca This question is from textbook Saxon Algebra 1

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
1st: 4y + 3x = -7
2nd: 3y + 2x = -6
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You can choose which variable you want to eliminate.
If you want to eliminate the y-terms, mutiply 1st
thru by 3 and 2nd thru by 4 to get:
3rd: 12y+9x=-21
4th: 12y+8x=-24
Now subtract 4th from 3rd to get:
x=-3
Substitute that into 1st or 2nd: it doesn't matter which:
4y+3(-3)=-7
4y=2
y=1/2
Solution:
x=-3 and y=1/2
Cheers,
Stan H.