SOLUTION: x= 12 y=8 z=3 (x/y)2 -3y-z/(x-y)2 =

SOLUTION: x= 12 y=8 z=3 (x/y)2 -3y-z/(x-y)2 =

Algebra.Com

Question 50303This question is from textbook Algebra 1
: x= 12 y=8 z=3

(x/y)2 -3y-z/(x-y)2 =
This question is from textbook Algebra 1

Answer by seawind(8) (Show Source): You can put this solution on YOUR website!
use substitution
(12/8)2-3*8-3/(12-8)*2
=3-24-3/4*2
=3-24-3/2
=-21-3/2
=-42/2-3/2
=-45/2
RELATED QUESTIONS
2x+3y-z x=2 y=-3... (answered by ikleyn)

Solve for the variable $x$ in terms of $y$ and $z$: xy + 2x = \frac{x - 2y + z}{3} + (x... (answered by yurtman)

y/4+z/4=z/3+x/3=x/2+y/2... (answered by ikleyn)

x+y=z then x+y-z=0 2(x+y)=2(z) 3(x+y)=3(z) 2x+2y=2z 3x+3y=3z 2x+2y-2z=0 (answered by ichudov)

Convert to augmented matrix. x+y+z=1 -x=2+z-3y... (answered by tommyt3rd)

1) x+y=9 x+2y=13 x= y= 2) 3x+7y= 24 9x+5y=24 x= y= 3) 4x+y=17 2x+3y+21 x= (answered by Fombitz)

Solve the system for x, y and z: x+y+z=7 2x+y-z=4... (answered by TigerAlgebra)

(x+y+z)^2=? (answered by jim_thompson5910)

solve using elimination x+y+z=-2 x+y-z=2... (answered by Edwin McCravy)