SOLUTION: The problem is : 3(y+4) = 2(y+6) You need to solve for y. So, this is what I did. 3y + 12 = 2y + 12 I subtracted the 12 from both sides to get : 3y = 2y. But, now

Algebra.Com
Question 489959: The problem is :
3(y+4) = 2(y+6)
You need to solve for y. So, this is what I did.
3y + 12 = 2y + 12
I subtracted the 12 from both sides to get :
3y = 2y.
But, now I don't know what to do.

Answer by deborabr(181)   (Show Source): You can put this solution on YOUR website!
3(y+4) = 2(y+6)
3y + 12 = 2y + 12
here is correct but now you have to do:
3y-2y=12-12
y=0

RELATED QUESTIONS

How would you solve the following using the quadratic formula - showing step by step? I... (answered by mukhopadhyay)
Hello, I need help with my summer assignment. It's a two-part question. The first part... (answered by josgarithmetic,ikleyn)
I have tried to figure out how to properly graph this problem however, when I looked at... (answered by Fombitz,algebrapro18)
Hi: I wondered if you could check this problem for me... Solve each system by the... (answered by scott8148)
Using Substitution 4x + 2y = 1 2x + 3y = .70 Solving for X in the first problem 4x... (answered by Fombitz)
Can you please tell me if i got these correct? Im doing a practice test to study for my... (answered by Edwin McCravy,solver91311)
Subtract: write your answer in simplest form. y-2/y+3 subtract y/2y+6 a. y-2/y+3 (answered by ankor@dixie-net.com)
I need help on knowing how to solve linear systems in form of fractions. the problem: (answered by user_dude2008,amoresroy)
6.1 I. Solve each system by graphing, and classify the system as dependent or... (answered by Flake)