SOLUTION: The problem is :
3(y+4) = 2(y+6)
You need to solve for y. So, this is what I did.
3y + 12 = 2y + 12
I subtracted the 12 from both sides to get :
3y = 2y.
But, now
Algebra.Com
Question 489959: The problem is :
3(y+4) = 2(y+6)
You need to solve for y. So, this is what I did.
3y + 12 = 2y + 12
I subtracted the 12 from both sides to get :
3y = 2y.
But, now I don't know what to do.
Answer by deborabr(181) (Show Source): You can put this solution on YOUR website!
3(y+4) = 2(y+6)
3y + 12 = 2y + 12
here is correct but now you have to do:
3y-2y=12-12
y=0
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