SOLUTION: PROBLEM...find the 2-digit number whose tens digit is 3 less than the units digit. The original number is 6 more than 4 times the sum of the digits..... I HAVE SEVERAL PROBLEMS

Question 482070: PROBLEM...find the 2-digit number whose tens digit is 3 less than the units digit. The original number is 6 more than 4 times the sum of the digits.....
I HAVE SEVERAL PROBLEMS SIMILAR TO THIS ONE AND I AM WONDERING IF THERE IS A STANDARD FORMULA THAT APPLIES TO THIS TYPE OF QUESTION. THANKS!
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
There is no "standard formula."

You have to use some algebra by giving some digit a name. Suppose the units digit is u. Then the tens digit is u-3. The original number is 6 more than 4 times the sum of the digits means:

(I simply converted the statement into an equation, with the "original number" being 10(u-3) + u).

Solving for u,

(simply expand both sides)

Hence, the units digit is 8 and the tens digit is 5. We can check since 58 is 6 more than the 4 times the sum of the digits (13).
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