SOLUTION: The equation h = - 16t^2 + 112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft, where t is the time after the arrow leaves the ground.

Question 47545: The equation h = - 16t^2 + 112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to reach a height of 180ft.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The equation h = - 16t^2 + 112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to reach a height of 180ft.
Let h=180 and solve for t, as follows:
180=-16t^2+112t
-16t^2+112t-180=0
-4(2t-5)(2t-9)=0
The arrow is at height 180 ft at time=5/2 sec. and at time=9/2 sec.
Cheers,
Stan H.

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