SOLUTION: The length of a rectangle is 3 cm more than 4 times its width. If the area of the rectangle is 79 cm^2, find the dimensions of the rectangle to the nearest thousandth. To start

Question 46778: The length of a rectangle is 3 cm more than 4 times its width. If the area of the rectangle is 79 cm^2, find the dimensions of the rectangle to the nearest thousandth.
To start should it be - using x for the width and l for the length
l = s(4) + 3
Is there anyone who can help and thank you.
Found 2 solutions by Nate, Earlsdon:
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
width = w
length = 4w + 3

width: can not have negative measurement
width:
length
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let the length of the rectangle be L and its width be W. Acoording to the story:
L = 4W+3 cm and the area is:
L X W = 79 cm^2 Substitute the L in the second equation with its equivalent (4W+3) and solve for W.
(4W+3) X W = 79 cm^2 Simplify and solve for W.
Subtract 79 from both sides of the equation.
Use the quadratic formula to solve for W:

Only the positive answer is meaningful for the width.
and:

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