SOLUTION: I have a couple problems I need help with. I did the first one, I just am having a hard time with the second one. Please help me :)
a) 2(y-1)^2 = 4(y+1)^2
b) x/3 - x/12 =
Algebra.Com
Question 466737: I have a couple problems I need help with. I did the first one, I just am having a hard time with the second one. Please help me :)
a) 2(y-1)^2 = 4(y+1)^2
b) x/3 - x/12 = -4
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
a) 2(y-1)^2 = 4(y+1)^2
---
2(y^2-2y+1) = 4(y^2+2y+1)
Divide both sides by 2 to get:
-----
y^2-2y+1 = 2y^2+4y+2
-----
y^2+6y+1 = 0
y = [-6 +- sqrt(36-4*1)]/2
y = [-6 +- 4sqrt(2)]/2
---
y = -3+-2sqrt(2
====================================
b) x/3 - x/12 = -4
Multiply thru by 12 to get:
4x-x = -48
3x = -48
x = -16
=================
Cheers,
Stan H.
RELATED QUESTIONS
For the following function {{{g(x)=-4x^2+8x+3}}} I am to determine wherether this... (answered by solver91311)
Good day,I need some help with some problems that are given me a hard time,it's square... (answered by tutorcecilia)
3/4-sqrt(7). Rationalize the denominator. I am having a hard time with this one. Can you... (answered by nerdybill)
Can I also have help with this one...
solve for x and y for x-y=4 and x+y=4
I am... (answered by navytutor)
I am having a hard time with Algebra and need some help I have to graph and Identify the... (answered by Alan3354)
I need help with a couple problems. Here is one. 0.4 times 10 to the negative 2nd... (answered by CubeyThePenguin)
A MAN IS FIVE YEARS OLDER THAN HIS WIFE. THIRTEEN YEARS AGO HE WAS TWICE HER AGE. HOW OLD (answered by stanbon)
hello my name is lisa, how are you? I am having trouble with a couple problems but some i (answered by nerdybill)
hello i am an eight grader and i am having a hard time with quadratic equations they... (answered by Edwin McCravy)