SOLUTION: The equation h = -16t^2 – 32t + 112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112ft/s, where t is the time after the arrow leaves t

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Question 45912: The equation h = -16t^2 – 32t + 112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112ft/s, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to reach a height of 180 ft.
Not sure where to start on this one.
Thanks for help

Answer by Nate(3500)   (Show Source): You can put this solution on YOUR website!
I do not know how you get -32t ....



Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -320 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -320 is + or - .

The solution is

Here's your graph:


V(2.5,100)
The highest the arrow will go is 100ft.

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