SOLUTION: Solve the linear system by using substitution. x=6-4y, 2x-3y=1

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Question 454313: Solve the linear system by using substitution. x=6-4y, 2x-3y=1
Answer by algebrahouse.com(1659) About Me  (Show Source):
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x = 6 - 4y
2x - 3y = 1

2x - 3y = 1 {bottom equation}
2(6 - 4y) - 3y = 1 {substituted 6 - 4y, in for x, into bottom equation}
12 - 8y - 3y = 1 {used distributive property}
12 - 11y = 1 {combined like terms}
-11y = -11 {subtracted 12 from both sides}
y = 1 {divided both sides by -11}

x = 6 - 4y {top equation}
x = 6 - 4(1) {substituted 1, in for y, into top equation}
x = 6 - 4 {multiplied 4 by 1}
x = 2 {subtracted}

x = 2 and y = 1
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