SOLUTION: Factor completely:y^2-16
Algebra.Com
Question 435728: Factor completely:y^2-16
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
y^2-16
can be rewritten as:
y^2-4^2 (which is a "difference of squares")
which factors to:
(y-4)(y+4)
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