SOLUTION: Given the quadriatic function f(x) = x^2 - 14x + 49, find the value of x such that f(x) = 36

SOLUTION: Given the quadriatic function f(x) = x^2 - 14x + 49, find the value of x such that f(x) = 36

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Question 428161: Given the quadriatic function f(x) = x^2 - 14x + 49, find the value of x such that f(x) = 36
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Given the quadriatic function f(x) = x^2 - 14x + 49, find the value of x such that f(x) = 36
.
Set f(x) to 36 and solve for x:
36 = x^2 - 14x + 49
0 = x^2 - 14x + 13
0 = (x-13)(x-1)
x = {1, 13}
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