SOLUTION: George is 6 times as old as Bobby. The sum of their ages is 98. How old is each now?
Algebra.Com
Question 421458: George is 6 times as old as Bobby. The sum of their ages is 98. How old is each now?
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
"George is 6 times as old as Bobby. The sum of their ages is 98. How old is each now?"
x = Bobby
6x = George {George is six times as old as Bobby}
x + 6x = 98 {sum of ages is 98}
7x = 98 {combined like terms}
x = 14 {divided both sides by 7}
6x = 84 {substituted 14, in for x, into 6x}
Bobby is 14 and George is 84
www.algebrahouse.com
RELATED QUESTIONS
Bobby is three times as old as Kelly. The sum of their ages is 46. How old is (answered by checkley79)
bobby is four times as old as his son tommy. Charlie is two years older than his brother... (answered by Olasko)
Bobby is 3 years older than Chris.Last year,the sum of their ages was 39.How old is each... (answered by AnimalLover,MathTherapy)
Cecile is now four times as old as Daisy.Five years ago, the sum of their ages was 45.How (answered by josmiceli,Caxxx)
Alvin is now four times as old as Benjamin. Five years ago, the sum of their ages was 45... (answered by josmiceli)
Cecile is now four times as old as daisy. Five years ago, the sum of their ages was 45.... (answered by lwsshak3)
Alvin is now 4 times as old as benjamin. Five years ago, the sum of their ages was 45... (answered by addingup)
Maria is twice as old as John. The sum of their ages is 55. How old is each... (answered by ikleyn)
Cecile is now four times as old as daisy . Five years ago , the sum of their two ages was (answered by josmiceli)