SOLUTION: The length of a rectangle is 8 inches more than twice its width. If the perimeter of the rectangle is 28 inches, find the width of the rectangle.

Question 39397: The length of a rectangle is 8 inches more than twice its width. If the perimeter of the rectangle is 28 inches, find the width of the rectangle.
Found 2 solutions by fractalier, Earlsdon:
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Let L be length and W be width. Then
L = 8 + 2W
But the formula for perimeter is
P = 2L + 2W = 28 so
we substitute and get
2(8 + 2W) + 2W = 28
16 + 4W + 2W = 28
6W + 16 = 28
6W = 12
W = 2 inches, the width.
Therefore L = 8 + 2(2) = 12
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Start with the formula for the perimeter of a rectangle:
We know that P = 28"
We also know that L = 2W+8, substitute this into the formula.
Simplify and solve for W.

Subtract 16 from both sides of the equation.
Divide both sides by 6.

The width is 2 inches.
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