SOLUTION: 32x + 23y = 10,100 12x + 14y = 5400 substituttion the varible. I selected equation 2 first to solve for y, but couldn't get y by itself. please help... subtracted 12x from b

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Question 392211: 32x + 23y = 10,100
12x + 14y = 5400
substituttion the varible. I selected equation 2 first to solve for y, but couldn't get y by itself. please help...
subtracted 12x from both sides of 12x + 14y = 5400 I got:
14y = 5400-12x....what is my next step?

Found 2 solutions by edjones, stanbon:
Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website!
divide the equation by 14.

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!

32x + 23y = 10,100
12x + 14y = 5400
substitute the varible. I selected equation 2 first to solve for y, but couldn't get y by itself. please help...
subtracted 12x from both sides of 12x + 14y = 5400 I got:
14y = 5400-12x....what is my next step?
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y = (2700-6x)/7
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Substitute to get:
32x + 23[2700-6x]/7 = 10100
32x + (62100-138x)/7 = 10100
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Multiply thru by 7 to get:
224x + 62100 - 138x = 7*10100
86x = 8600
x = 100
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Substitute to solve for "y":
y = (2700-6*100)/7
y = (2100)/7
y = 300
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Cheers,
Stan H.