SOLUTION: find two positive numbers so that twice their sum equals their product and one number is 9 times the other number

Question 390882: find two positive numbers so that twice their sum equals their product and one number is 9 times the other number
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
: find two positive numbers so that twice their sum equals their product and one number is 9 times the other number
:
Let x = one number
then
9x = the other number
:
2(9x + x) = x * 9x
2(10x) = 9x^2
20x = 9x^2
divide both sides by x
20 = 9x
x = is one number
9* = 20 is the other number
:
:
See if this is true in the original statement:
"two positive numbers that twice their sum equals their product"
2( + 20) = * 20
2( + ) =
2() =

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