SOLUTION: a^2+b^2=52 and a^2-b^2= 20 Solve for b

SOLUTION: a^2+b^2=52 and a^2-b^2= 20 Solve for b

Algebra.Com

Question 36932: a^2+b^2=52 and a^2-b^2= 20 Solve for b
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
a^2+b^2=52 .......................I
and a^2-b^2= 20............................II
Solve for b
EQN.I-EQN.II GIVES
A^2+B^2-(A^2-B^2)=52-20=32
A^2+B^2-A^2+B^2=32
2B^2=32
B^2=32/2=16
B=+4 OR -4
RELATED QUESTIONS
Hi tutor, please try to help solve this question for me please!! If a^2+b^2=52 and... (answered by josgarithmetic)

C^2=a^2+b^2 solve for... (answered by jim_thompson5910)

Solve for B. a^2 + b^2 =... (answered by solver91311,wilft1)

A=1/2(b+B) solve for... (answered by Fombitz)

A=(1/2)h (B+b) solve for B (answered by stanbon)

A=1/2h(b+B) Solve for h and solve for B : A = {{{1/2}}}h(b+B) (answered by ankor@dixie-net.com)

A = 1h(B + b) (for b) 2 (answered by funmath)

c=√(a^2+b^2 ) Solve for... (answered by josgarithmetic)

solve... (answered by tommyt3rd)