Hi, *Note: the vertex form of a parabola, where(h,k) is the vertex f(x) = x^2 + 6x + 18 completing the square f(x) =(x+3)^2 -9 + 18 = 1*(x+3)^2 + 9 a = 1, a positive number, therefore parabola opens upward vertex is (-3,9) this is a minimum value.