SOLUTION: A bus traveling at a constant rate of 30 miles per hour left the city at 11:45 a.m. A car following the bus at 45 miles per hour left the city at noon. At what time did the car ca

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Question 352513: A bus traveling at a constant rate of 30 miles per hour left the city at 11:45 a.m. A car following the bus at 45 miles per hour left the city at noon. At what time did the car catch up with the bus?
Answer by robertb(5830)   (Show Source): You can put this solution on YOUR website!
Let t = the amount of time the car would catch up with the bus. The car took off 15 minutes, or 1/4 of an hour after the bus. Therefore the amount of time before the car catches up with the bus is . From the formula
(or distance = rate x time),
,
,
,
.
So the car would catch up with the bus after 3/4 hr, or 45 minutes.

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