SOLUTION: 3[(2-3)^2 + (6 - 4)^2]
I have not done this in quite a while and was needing some assistance. Can you please take a look at it and qive me some help. Thank you very much.
Algebra.Com
Question 347721: 3[(2-3)^2 + (6 - 4)^2]
I have not done this in quite a while and was needing some assistance. Can you please take a look at it and qive me some help. Thank you very much.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
3[(2-3)^2 + (6 - 4)^2] ... Start with the given expression.
3[(-1)^2 + (2)^2] ... Subtract.
3[1 + 4] ... Square each term.
3[5] ... Add
15 ... Multiply
So 3[(2-3)^2 + (6 - 4)^2] = 15
If you need more help, email me at jim_thompson5910@hotmail.com
Also, feel free to check out my tutoring website
Jim
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