SOLUTION: how can i solve (Z+5)-7=(Z-7)+5
and
-(Y+5)-(2+7y)+8y=3y-8
tha parenthesis gets me off track can you please give me the steps to similar problems?
thank you so much
Algebra.Com
Question 338204: how can i solve (Z+5)-7=(Z-7)+5
and
-(Y+5)-(2+7y)+8y=3y-8
tha parenthesis gets me off track can you please give me the steps to similar problems?
thank you so much
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve
(Z+5)-7=(Z-7)+5
Z+5-7 = Z-7+5
Z-2 = Z-2
Z = Z
--
The original equation is an identity and
is true for all values of Z.
-------------------------------------
and
-(Y+5)-(2+7y)+8y=3y-8
-Y-5 -2-7y+8y = 3y-8
-7 = 3y-8
3y = 1
y = 1/3
==============
Cheers,
Stan H.
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