SOLUTION: A diver jumps from a 48 foot cliff into the ocean below with an initial velocity of 8 ft/sec. The height of the diver from the ocean after t sec is given by h = -16t2 + 8t + 48. Wh

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Question 300908: A diver jumps from a 48 foot cliff into the ocean below with an initial velocity of 8 ft/sec. The height of the diver from the ocean after t sec is given by h = -16t2 + 8t + 48. When does the diver hit the water?
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
h = -16t2 + 8t + 48. When does the diver hit the water?
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When h = 0
-16t^2 + 8t + 48 = 0
Solve for t
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=49 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: -1.5, 2. Here's your graph:


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t = 2 seconds

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