SOLUTION: Do the operation and simplify the answer.
{{{(5x^2+21x+4)/(x^2-16)}}} / {{{(5x+1)/(x-2)}}}
I need help with this please.
Algebra.Com
Question 294481: Do the operation and simplify the answer.
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I need help with this please.
Found 2 solutions by unlockmath, richwmiller:
Answer by unlockmath(1688) (Show Source): You can put this solution on YOUR website!
Hello,
This / can be written as follows:
{(5x^2+21x+4)/(x^2-16)} multiplied by {(x-2)/(5x+1)} The first fraction can be rewritten as:
{(5x+1)(x+4)/(x-4)(x+4)}times{(x-2)/(5x+1)} Notice the (5x+1) and the (x+4)cancels out to leave us with:
(x-2)/(x-4)
Make sense?
RJ
There's a book I wrote on the basics you'd like:
www.math-unlock.com
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
This all reduces to (x-2)/(x-4)
First division is the same as multiplication by the reciprocal
Next factor (x^2-16)=(x-4)(x+4)
Factor 5x^2+21x+4 = (5x+1)*(x+4)
Cancel out (5x+1) and (x+4)
and we have (x-2)/(x-4)
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