SOLUTION: Can you help me with this?
Fill in the blanks.
a) {{{14x^2-21=(______)(2x^2-3)}}}
b) {{{3x^2+5x-28=(___________ )(x+4)}}}
Thank you!
Algebra.Com
Question 286538: Can you help me with this?
Fill in the blanks.
a)
b)
Thank you!
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
Factor out the common value 7 from each term.
14x^2-21=7(x^2-3)
a)
Factor the equation:
Factor 3x^3=3x & x
Factor -28=-7 & 4
Now combine the terms.
(3x-7)(x+4)
Prove using the FOIL technique.
3x^2-7x+12x-28
3x^2+5x-28
b)
RELATED QUESTIONS
Can you help me solve the problem {{{ 14x^2+11x+3= 2x^2-3x+3}}}. thank... (answered by nerdybill)
(Can someone please help me with this question, thanks)
Find the indicated outputs for... (answered by richard1234)
Dear ma'am or sir,
Can you please help me how to simplify this following algebraic... (answered by josmiceli)
please help with factoring
3x^2y^3-3x^2y
x^2+144
5x^2-14x+16
2x^2+11x-9
Thank... (answered by jim_thompson5910)
Fill in the blanks, to make a true equation:
\frac{2x^4 - 3x^3 - x^2 + 4x - 4}{x^2 +... (answered by CPhill)
Hi,
Can you please help me with this multiplication problem... (answered by Alan3354)
Can you please help me out with this?
2/x+3/3x / 1/3x-1/2x
Thank you so... (answered by ankor@dixie-net.com)
Can you please help me solve this: Which term in each of the following has the lowest... (answered by checkley75)
x - 4 < 5
x - 5 ≤ 6
2x + 1/2 > 7
3x + 4 ≤ 2x
2 < x - 2 < 7
2 < 3x + 2... (answered by Fombitz)