SOLUTION: using this formula, solve; A+B=(A+B)(A�-AB+B�) or A-B=(A-B)(A�+AB+B�) 1. 27y�-1 my answer; y(9y-1)(3y�+9y+1) in this problem, contain polynomials in several variables. Fac

Question 278380: using this formula, solve; A+B=(A+B)(A�-AB+B�) or A-B=(A-B)(A�+AB+B�)
1. 27y�-1
my answer; y(9y-1)(3y�+9y+1)
in this problem, contain polynomials in several variables. Factor
each polynomial completely & check using multiplication.
2. 16a�b�-4ab�
my answer; 4ab�(2a+1)(2a-1)
Use factoring to solve each quadraic equation. Check by substitution
or by graphing utility & identifying x-intercepts.
3.y(y+9)=4(2y+5)
my answer; (4,-5)

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
using this formula, solve; A^3+B^3=(A+B)(A�-AB+B�) or A^3-B^3=(A-B)(A�+AB+B�)
1. 27y�-1 = (3y^3-1^3) = (3y-1)(9y^2+3y+1)
-------------------------------------------------
in this problem, contain polynomials in several variables. Factor
each polynomial completely & check using multiplication.
2. 16a�b�-4ab� = 4ab^2(4a^2-1) = 4ab^2(2a-1)(2a+1)
-------------------------------------------

Use factoring to solve each quadraic equation. Check by substitution
or by graphing utility & identifying x-intercepts.
3.y(y+9)=4(2y+5)
y^2+9y = 8y+20
y^2+y-20 = 0
(y+5)(y-4)=0
y = -5 or y = 4
=============================
Note: (4,-5) is not the proper way to express the answer.
=============================
Cheers,
Stan H.

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