SOLUTION: find a number whose half exceeds its third by the sum of its digits. give the formula.

Question 277161: find a number whose half exceeds its third by the sum of its digits. give the formula.
Answer by CharlesG2(834) (Show Source): You can put this solution on YOUR website!
find a number whose half exceeds its third by the sum of its digits. give the formula.
x = a number
y = sum of x's digits
half exceeds its third by an amount (in this case the amount is the sum of the digits of the number) means that the half equals the third plus the amount
1/2 * x = 1/3 * x + y (convert to 6ths)
3/6 * x = 2/6 * x + y
1/6 * x = y (multiply both sides by 6)
x = 6y
so that means the number will be 6 times the sum of its digits
example answer would be 54, 6 * (5 + 4) = 6 * 9 = 54
27 = 18 + 9 = 27

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