SOLUTION: Find three consecutive positve even integers such that the difference in the
squares of the first and third is 80
We have figured out x but I can't write the equation correctly
Algebra.Com
Question 27638: Find three consecutive positve even integers such that the difference in the
squares of the first and third is 80
We have figured out x but I can't write the equation correctly
Answer by Paul(988) (Show Source): You can put this solution on YOUR website!
Consecutive integers = x, x+2, x+4
8x=64
x=8
8+2=10
8+4=12
Hence, the 3 integers are 8, 10 and 12.
Paul.
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