SOLUTION: The cost, in millions of dollars, to remove x % of pollution in a lake modeled by C=6000/200-2x. Answer the following questions:
a. What is the cost to remove 75% of the pollutant
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Question 272497: The cost, in millions of dollars, to remove x % of pollution in a lake modeled by C=6000/200-2x. Answer the following questions:
a. What is the cost to remove 75% of the pollutant?
b. Describe what happens to the cost as the percentage of pollution removed increases from 75% and moves toward 100%.
c. According to this model, is it possible to remove 100% of the pollution? Why or why not?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The cost, in millions of dollars, to remove x % of pollution in a lake modeled by C=6000/200-2x.
Answer the following questions:
a. What is the cost to remove 75% of the pollutant?
6000/(200-2*75) = 120 million
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b. Describe what happens to the cost as the percentage of pollution removed increases from 75% and moves toward 100%.
The cost rises because the denominator of 6000 gets smaller.
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c. According to this model, is it possible to remove 100% of the pollution? Why or why not?
No because that would make the denominator zero.
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Cheers,
Stan H.
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